weight 66kg height 166cm what is the bmi

Table od Content

## 1. weight 66kg height 166cm what is the bmi

**Answer:**

39.76

**Explanation:**

thats my answer in my brain

**Answer:**

23.91

**Explanation:**

yan po yung bmi niyo

## 2. height 1.25 meters weight 66kg. BMI

BMI Formula

weight kg

(height m)²

66kg

(1.25m)²

66kg

1.5625m

**42.24**

**Answer:**

42.2 Is your BMI

**Step-by-step explanation:**

weight (in kilograms)

height (in meters)

66 = 66 = 42.2(1.25)² (1.56)

## 3. What is the change in Carlo's weight from 66kg to 73kg?

**Answer:**

7kg

**k****a****si ****what ****is ****the ****change ****so ****pag ****minusin ****mo ****lng**

## 4. The moon has a mass of 7.34 x 10^22kg and a radius of 1.74 x 10^6 meters. if you have a mass of 66kg, how strong is the force between you and the moon?

**C****a****l****c****u****l****a****t****i****n****g**** ****G****r****a****v****i****t****a****t****i****o****n****a****l**** ****F****o****r****c****e****.**

Given

Mass of the Moon (m₁) = 7.34 x 10²² kgMy mass (m₂) = 66 kgRadius (r) = 1.74 x 10⁶ mGravitational Constant (G) = 6.674 x 10⁻¹¹ m³ / kg • s²Gravitational Force (Fg) = ?

Use **N****e****w****t****o****n****'****s**** ****L****a****w**** ****o****f**** ****U****n****i****v****e****r****s****a****l**** ****G****r****a****v****i****t****a****t****i****o****n**** **to calculate the gravitational force.

Fg = Gm₁m₂ / r²

Fg = (6.674 x 10⁻¹¹ m³ / kg • s²)(7.34 x 10²² kg)(66 kg) / (1.74 x 10⁶ m)²

Fg = (6.674 x 10⁻¹¹ m³ / kg • s²)(7.34 x 10²² kg)(66 kg) / (3.0276 x 10¹² m²)

Fg = (6.674 x 10⁻¹¹ m³ / kg • s²)(4.844 x 10²⁴ kg) / (3.0276 x 10¹² m²)

Fg = (6.674 x 10⁻¹¹ m³ / kg • s²)(4.844 x 10²⁴ kg) / (3.0276 x 10¹² m²)

Fg = (3.2328856 x 10¹⁴ m³ / s²) / (3.0276 x 10¹² m²)

**F****g**** ****=**** ****1****0****6****.****7****8**** ****N**

#CarryOnLearning

## 5. How much force is needed to accelerate a 66kg skier 1m/sec/sec?

**Explanation:**

using the formula f=ma

f= 66kg(1m/s²)

f= 66kg•m/s² or 66N

## 6. the moon has a mass of 7.34^10²²kg and a radius of 1.74^10 6 meters. if you have a mass 66kg how strong is the force between you and the moon?

**Calculating Gravitational Force.**

Given

Mass of the Moon (m₁) = 7.34 x 10²² kgMy mass (m₂) = 66 kgRadius (r) = 1.74 x 10⁶ mGravitational Constant (G) = 6.674 x 10⁻¹¹ m³ / kg • s²Gravitational Force (Fg) = ?

Use** Newton's Law of Universal Gravitation** to calculate the gravitational force.

Fg = Gm₁m₂ / r²

Fg = (6.674 x 10⁻¹¹ m³ / kg • s²)(7.34 x 10²² kg)(66 kg) / (1.74 x 10⁶ m)²

Fg = (6.674 x 10⁻¹¹ m³ / kg • s²)(7.34 x 10²² kg)(66 kg) / (3.0276 x 10¹² m²)

Fg = (6.674 x 10⁻¹¹ m³ / kg • s²)(4.844 x 10²⁴ kg) / (3.0276 x 10¹² m²)

Fg = (6.674 x 10⁻¹¹ m³ / kg • s²)(4.844 x 10²⁴ kg) / (3.0276 x 10¹² m²)

Fg = (3.2328856 x 10¹⁴ m³ / s²) / (3.0276 x 10¹² m²)

**Fg = 106.78 N**

#CarryOnLearning

## 7. A man has mass of 66kg on earth what is his weight in Newtoons?

**Answer:**

answer is 66 kilograms-force = 647.2389 newtons

## 8. How much force is needed to accelerate a 66kg skier at 2m/sec2

ANSWER:

132 N

EXPLANATION:

**Force** is the product of the **mass** and **acceleration due to gravity** of an object

Force = mass × acceleration due to gravity

F = mg

The SI unit of** ****force (F)** is **newton (N)** and **1 N = 1 kg.m/s² **

Given:

m = 66 kg

g = 2 m/s²

Finding:

F = ?

F = mg

F = (66 kg)(2 m/s²)

F = (132 kg.m/s²)

F = 132 N

Therefore the force needed to accelerate a 66 kg skier at 2 m/s² is **132 N**

#AnswerForTrees

#BrainlyLearnAtHome

**Answer:**

132 N

**Explanation:**

66kg×2m/s²

132N

#AnswerForTrees

## 9. A baby was born weighing 2.7 kilograms, it is equal to how many pounds?A. 5 poundsB. 6 poundsC. 7 poundsD. 8 pounds

5.94 lb

Weight of Baby is 2.7 kg.. To convert the weight of Baby into pound, Multiply by 2.20. Therefore, 2.7 × 2.20 = 5.94 lb.

**Answer:**** **A**.**** **5 pounds.

## 10. If there is 3kilos of meat how many pounds it will bea. 6.60 poundsb. 6.66 poundsc. 6.63 poundsd. 6.69 pounds

**Answer:**

A.6.60 pounds

**Explanation:**

no need explation cause halata naman eh

#carryonlearning

#helpinghand

## 11. BMIW = 66kgH = 1.49dapat po May sulution

**Answer:**

BMI = weight/height

66kg/(1.49m)²

66kg/2.22

BMI = 29.7

## 12. 1 kilogram of sugar is equivalent to ___ pound.A. 2.25 poundB. 2.21 poundC. 221 poundB. 22.1 pound

**Answer:**

A. po

**Explanation:**

thats the answer

thanks

**Answer:**

Sagot po ay

B. 2.21

**Explanation:**

Because 1 kl is equal to 2.20 pounds

## 13. If 16 ounces is equal to 1 pound? What is the equivalent of 4 ounces in pound?*1 pointA. 1/8 poundB. ¼ poundC. 1/3 poundD. ½ pound

**Answer:**

1/8 pound

**Explanation:**

if you convert 4 ounces into pounds the result is 0.25 if you convert it into fraction the result is 1/8 :D

## 14. A man climbs on to a wall that is 7 m high and gains 4, 525J of potential energy. What is the mass of the man? * 2 points a.66kg b.646kg c.9.8kg d.69kgpasagutt

**Answer:**

45.9kg

Becoz Man cannot climb at 7m

## 15. How many pounds are there in 3 tons? 3,000 pounds4,000 pounds5,000 pounds6,000 pounds

**Answer:**

3000 pounds

**Step-by-step explanation:**

multiply by 10

Follow for more

## 16. How much force is needed to accelerate a 66kg skier at 2m/s²? given:solution:final answer:

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The force acting on an object is given by

[tex]\boxed{F = ma}[/tex]

where:

F = force

m = mass

a = acceleration

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for F

F = ma

F = (66 kg)(2 m/s²)

[tex]\boxed{F = \text{132 N}}[/tex]

Therefore, the force needed is **132 N.**

[tex]\\[/tex]

#CarryOnLearning

## 17. how much force is needed to accelerate a 66kg skier 1 m / sec/ sec ?

**Answer:**

Answer: = 66 kg x 2 m/s^2 = 132 N. Thus, a force of 132 N is needed to accelerate a skier, having a mass of 66 kg, by 2 m/s^2

## 18. how much force is needed to accelerate a 66kg skier at 2m/sec²?

**Answer:**

use paper and book and read your book and get ballpen then star drwaing

**Answer:**

**F= 132N is the force needed to accelerate a 66kg skier at 2m/sec²?**

**Explanation:**

**By Newton's second law**

**F = ma**

**Plug in the numbers:**

**F=66kg(2ms2)**

**F= 132N**

## 19. 3. How heavy is 4 gallons of kerosene?25.566 pounds26.656 pounds27.665 pounds28.658 pounds

**Answer:**

26.656 Ang sagot

**Step-by-step explanation:**

basta 26.656

## 20. 3. How much Force is needed to accelerate a 66kg skier 1m/s2

**Answer:**

66N

**Explanation:**

F= ma

F=(66kg)(1m/s²)

F=66N

## 21. After he lost 14 pounds, Jezryl weighed 172 pounds. Find Jezryl’s original weight. 158 pounds186 pounds172pounds200 pounds

**Answer:**

The answer is 186 Pounds.

## 22. 1 kilogram of sugar is equivalent to ___ pound.A. 2.25 poundB. 2.21 poundC. 221 poundB. 22.1 pound

**Answer:**

b. 2.21 pound

**Explanation:**

hope helps

## 23. What is 1 kilogram in pounds? *1 point1.1 pounds2.2 pounds3.3 pounds4.4 pounds

Problem

What is 1 kilogram in pounds?

Choices

1 point

1.1 pounds

2.2 pounds

3.3 pounds

4.4 pounds

Answer

1 kg. = 2.205 pounds

2.2 pounds

Formula

for an approximate result, multiply the mass value by 2.205

#CarryOnLearning =)

**Answer:**

2.2 pounds

**Step-by-step explanation:**

The mass m in pounds (lb) is equal to the mass m in kilograms (kg) divided by 0.45359237

Therefore, 1 kilogram (kg) is equal to 2.20462262185 pounds (lbs).

**1 kg = 2.2 pounds**

## 24. Lana loses 15 pounds during the month of August. A. –15 pounds B. 15 pounds C. 0 pounds

**Answer:**

A

**Step-by-step explanation:**

Bcs she losses 15 pound so the answer is - 15pounds

ANSWER:**A****.****-****1****5**** ****P****O****U****N****D****S**

#CarryOnLearning#MabuhayBrainly

## 25. How much force is needed to accelerate a 66kg skier 1m/sec/sec?

161.23466277272882822

## 26. How much force is needed to accelerate a 66kg skier at 2m/s2?

**Answer: Thus, a force of 132 N is needed to accelerate a skier, having a mass of 66 kg, by 2 m/s^2**

**Explanation:I HOPE IT HELPS ARIGATOU MINNA!**

## 27. What is the equivalent of 0.45 kilogram in Metric system if it will convert into pounds in English systema. 2.21 pounds b. 3.21 pounds c. 1.21 pounds d. 0.21 pounds

**Answer:**

its was 0.99/ 0.992 pounds po

**Explanation:**

cause 1kg is equivalent to 2.20 lbs/pounds

## 28. Covert 48 ounces into poundsA. 1 poundB. 2 poundsC. 3 poundsD. 4 pounds

**Answer:**

The answer is letter C. 3pounds

**Answer:**

c. 3 pound

**Explanation:**

sana makatulong

## 29. After he lost 15 pounds, Gabriel weighed 187 pounds. Find Gabriel'soriginal weight?202 pound200 pounds196 pounds190 pounds

**Answer:**

**2****0****2**** ****p****o****u****n****d**** ****i****s**** ****t****h****e**** ****o****r****i****g****i****n****a****l**** ****w****e****i****g****h****t**

**Step-by-step explanation:**

lost pounds - 15

after losing 15 pounds he weighed - 187

[tex]187 + 15 = 202[/tex]

## 30. 1 kilogram of sugar is equivalent______ pound a. 2.25 pound b. 2.21 pound c. 221 pound d. 22.1 pound

**Answer:**

B.2.21

**Explanation:**

I TRIED MY BESTTTT

**Answer:**

b. yata

**Explanation:**

kasi 1kg = 2.21 pound